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 Post subject: ppot and npot
PostPosted: Wed Jun 12, 2013 10:29 am 
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Joined: Mon Apr 08, 2013 1:13 pm
Posts: 15
Hello.

I'm looking at the "Opponent Modeling in Poker" paper (http://www.cs.virginia.edu/~evans/poker ... llings.pdf). On page 4 there is code for ppot and npot as well as an example breakdown for AdQc+3h4cJh.

Code:
         Ahead     Tied     Behind     Sum
Ahead    449005    3211     169504     621720
Tied     0         8370     540        8910
Behind   91981     1036     346543     439560


Rows correspond to where the hand was on flop and columns correspond to where it went on river. My problem is that the paper says ppot_2 = 0.208. But when I put the numbers into the formula I get a slightly different number:
(91981+1036*0.5)/(8910+439560) = 0.20625...

Am I doing something wrong?


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 Post subject: Re: ppot and npot
PostPosted: Thu Jun 13, 2013 10:53 am 
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Joined: Mon Apr 08, 2013 1:13 pm
Posts: 15
The only explaination I have is that the authors actually mean to have only 1/2 of the total ties in the denominator.

There is another article that has exactly such formula.

And here is another person that uses the formula with 1/2 ties in the denominator.


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 Post subject: Re: ppot and npot
PostPosted: Thu Jun 13, 2013 11:32 am 
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Joined: Wed May 15, 2013 10:15 pm
Posts: 42
Did you try to play preflop with hand strenght ?
Is it better than a static approach like "Sklansky tables" or is it similar?


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 Post subject: Re: ppot and npot
PostPosted: Fri Jun 14, 2013 4:40 am 
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Joined: Mon Apr 08, 2013 1:13 pm
Posts: 15
No, haven't tried that. So far have only been using E[HS] and E[HS^2] for preflop bucketing.


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 Post subject: Re: ppot and npot
PostPosted: Fri Jun 14, 2013 6:12 am 
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Joined: Thu Feb 28, 2013 2:39 am
Posts: 437
Why not just use an unabstracted preflop, assuming disconnected rounds?


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