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ppot and npot http://poker-ai.org/phpbb/viewtopic.php?f=24&t=2514 |
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Author: | alex [ Wed Jun 12, 2013 10:29 am ] |
Post subject: | ppot and npot |
Hello. I'm looking at the "Opponent Modeling in Poker" paper (http://www.cs.virginia.edu/~evans/poker ... llings.pdf). On page 4 there is code for ppot and npot as well as an example breakdown for AdQc+3h4cJh. Code: Ahead Tied Behind Sum Ahead 449005 3211 169504 621720 Tied 0 8370 540 8910 Behind 91981 1036 346543 439560 Rows correspond to where the hand was on flop and columns correspond to where it went on river. My problem is that the paper says ppot_2 = 0.208. But when I put the numbers into the formula I get a slightly different number: (91981+1036*0.5)/(8910+439560) = 0.20625... Am I doing something wrong? |
Author: | alex [ Thu Jun 13, 2013 10:53 am ] |
Post subject: | Re: ppot and npot |
The only explaination I have is that the authors actually mean to have only 1/2 of the total ties in the denominator. There is another article that has exactly such formula. And here is another person that uses the formula with 1/2 ties in the denominator. |
Author: | shadehs [ Thu Jun 13, 2013 11:32 am ] |
Post subject: | Re: ppot and npot |
Did you try to play preflop with hand strenght ? Is it better than a static approach like "Sklansky tables" or is it similar? |
Author: | alex [ Fri Jun 14, 2013 4:40 am ] |
Post subject: | Re: ppot and npot |
No, haven't tried that. So far have only been using E[HS] and E[HS^2] for preflop bucketing. |
Author: | cantina [ Fri Jun 14, 2013 6:12 am ] |
Post subject: | Re: ppot and npot |
Why not just use an unabstracted preflop, assuming disconnected rounds? |
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