Poker-AI.org Poker AI and Botting Discussion Forum 2013-06-14T06:12:53+00:00 http://poker-ai.org/phpbb/feed.php?f=24&t=2514 2013-06-14T06:12:53+00:00 2013-06-14T06:12:53+00:00 http://poker-ai.org/phpbb/viewtopic.php?t=2514&p=4322#p4322 <![CDATA[Re: ppot and npot]]> Statistics: Posted by cantina — Fri Jun 14, 2013 6:12 am


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2013-06-14T04:40:20+00:00 2013-06-14T04:40:20+00:00 http://poker-ai.org/phpbb/viewtopic.php?t=2514&p=4321#p4321 <![CDATA[Re: ppot and npot]]> Statistics: Posted by alex — Fri Jun 14, 2013 4:40 am


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2013-06-13T11:32:31+00:00 2013-06-13T11:32:31+00:00 http://poker-ai.org/phpbb/viewtopic.php?t=2514&p=4320#p4320 <![CDATA[Re: ppot and npot]]> Is it better than a static approach like "Sklansky tables" or is it similar?

Statistics: Posted by shadehs — Thu Jun 13, 2013 11:32 am


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2013-06-13T10:53:48+00:00 2013-06-13T10:53:48+00:00 http://poker-ai.org/phpbb/viewtopic.php?t=2514&p=4319#p4319 <![CDATA[Re: ppot and npot]]>
There is another article that has exactly such formula.

And here is another person that uses the formula with 1/2 ties in the denominator.

Statistics: Posted by alex — Thu Jun 13, 2013 10:53 am


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2013-06-12T10:29:17+00:00 2013-06-12T10:29:17+00:00 http://poker-ai.org/phpbb/viewtopic.php?t=2514&p=4317#p4317 <![CDATA[ppot and npot]]>
I'm looking at the "Opponent Modeling in Poker" paper (http://www.cs.virginia.edu/~evans/poker ... llings.pdf). On page 4 there is code for ppot and npot as well as an example breakdown for AdQc+3h4cJh.

Code:
         Ahead     Tied     Behind     Sum
Ahead    449005    3211     169504     621720
Tied     0         8370     540        8910
Behind   91981     1036     346543     439560


Rows correspond to where the hand was on flop and columns correspond to where it went on river. My problem is that the paper says ppot_2 = 0.208. But when I put the numbers into the formula I get a slightly different number:
(91981+1036*0.5)/(8910+439560) = 0.20625...

Am I doing something wrong?

Statistics: Posted by alex — Wed Jun 12, 2013 10:29 am


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